CISC 7332X Spring 2022 Final Exam A 1. 111111Tbps (also accepted: 13889TBps [teraBYTES]) % number_of_bits = ( (100000 / 0.001) * 1000000000000 * 8) % seconds = (2000 / 1000)*60*60 % bps = number_of_bits / seconds % Tbps = bps / 1000000000000 = 111111.11111 2. 51.2 microseconds (also accepted: 50 microseconds) 3. b 4. c 5. a 6. b 7. d 8. 48Mbps % C = 16 * log(7+1)/log(2) = 48Mbps 9. 4 % C = (64-48) * log(15+1)/log(2) = 64Mbps; % (64 / ((64-48) * 2)) = 2 = log M / log(2) % M = 4 10. 12.1Mbps % err = 16 * -(0.96*log(0.96)/log(2) + 0.04*log(0.04)/log(2)) = 3.876675025318637 Mbps % cap = 16 - err = 12.12332497468136 Mbps = 12.1Mbps 11. 2.34MHz % 12.1 = X * (2 * log(6)/log(2)) % 12.1 / (2 * log(6)/log(2)) = 2.34 MHz 12. 35 % 12.1Mbps = 2.34Mhz * log(SNR+1)/log(2). % 12.1 / 2.34 = 5.17 = log(SNR+1)/log(2) % SNR = 35 13. 13MHz % 100Mbps = X * log( (4+0.020)/0.020 ) /log(2) % 100 / (log( (4+0.020)/0.020 ) /log(2)) = 13 MHz 14. -5.4770 % 10 * log ( 1.7 / 6 ) /log(10) = -5.4770 15. 10 %10 * log(10)/log(10) = 10 16. 350Mbps % SNR=127 % 50 * log(127+1)/log(2) = 350Mbps 17. d 18. b 19. e; full-duplex 20. d